Frustration Posted February 25, 2021 Posted February 25, 2021 11 minutes ago, Aspiring Writer said: You... You guys did what storming game theory does. (Also, pls send these numbers to BS, I would like to see his mind blow up.) We're not done yet
Aspiring Writer Posted February 25, 2021 Posted February 25, 2021 From Henceforth, the number of (Whatever we finally decided on) will now be dubbed a Metalbornplex. Suck it Matpat. 2
Frustration Posted February 25, 2021 Posted February 25, 2021 Just now, Aspiring Writer said: From Henceforth, the number of (Whatever we finally decided on) will now be dubbed a Metalbornplex. Suck it Matpat. How about Mistnumber?
Aspiring Writer Posted February 25, 2021 Posted February 25, 2021 Just now, Frustration said: How about Mistnumber? That works too.
dannnex male Posted February 25, 2021 Author Posted February 25, 2021 12 minutes ago, Bejardin1250 said: So what’s the final number? 3946456273736362783626728372 That’s my guess Add about 19 thousand digits to that, and you might be getting closer. (Not the number 19,000, 19,000 digits to the end of the number.) But yeah, we’re not done yet. Got a bunch of stuff to figure out how to add still.
Bejarden he/him Posted February 25, 2021 Posted February 25, 2021 *jaw drop* whaaaaaa good time to be a metallurgist
Halyo_Alex he/him Posted February 25, 2021 Posted February 25, 2021 6 minutes ago, Dannex said: Add about 19 thousand digits to that, and you might be getting closer. (Not the number 19,000, 19,000 digits to the end of the number.) But yeah, we’re not done yet. Got a bunch of stuff to figure out how to add still. "BUT I'M NOT DONE YET" "NOW THAT'S A LOT OF METALS" Rusts, I love my brain sometimes. 1
Retrac he/him Posted February 25, 2021 Posted February 25, 2021 Wait so does the you get one or them all still work. I mean just because we haven't seen one with 2 of the 16 normal metals (a very small percentage) doesn't mean it can't happen with one of the other.......
Frustration Posted February 25, 2021 Posted February 25, 2021 2 minutes ago, Retrac said: Wait so does the you get one or them all still work. I mean just because we haven't seen one with 2 of the 16 normal metals (a very small percentage) doesn't mean it can't happen with one of the other....... Who can burn Shardmetals/alloys is up in the air.
mathiau he/him Posted February 25, 2021 Posted February 25, 2021 35 minutes ago, Frustration said: Well Atium+Lerasium isn't Harmonium, so Hramonium+Skaisium is different from A+L+S, which would be different again if Harmon took up Dominion. I have no idea how to even begin calculating that I know, I've already taken care of that The 2^16-1 is count the number of individual Godmetal (I'm calling things like Harmonium or the metal that would be created by Harmony taking up Dominion individual Godmetals) Then I alloy any number (except 0) of these 2^16-1 Godmetal, that's 2^(2^16-1)-1 34 minutes ago, Dannex said: Does that include triple/quadruple/15ple groupings and all that? It does Quote And does it exclude impossible duplicated shard groupings? (Like a “Preservation-Ambition-Ambition” Shard) It does too
Halyo_Alex he/him Posted February 25, 2021 Posted February 25, 2021 4 minutes ago, mathiau said: I know, I've already taken care of that The 2^16-1 is count the number of individual Godmetal (I'm calling things like Harmonium or the metal that would be created by Harmony taking up Dominion individual Godmetals) Then I alloy any number (except 0) of these 2^16-1 Godmetal, that's 2^(2^16-1)-1 It does It does too I calculated that in the same calculator I used for the other one and got " 1.001764965 × 1019728 " Kinda small...
mathiau he/him Posted February 25, 2021 Posted February 25, 2021 Just now, Halyo_Alex said: I calculated that in the same calculator I used for the other one and got " 1.001764965 × 1019728 " Kinda small... I got the same result Yes, compared to the insane 2^(16!) it's small, but it's actually an insanely high number
dannnex male Posted February 25, 2021 Author Posted February 25, 2021 18 minutes ago, mathiau said: I know, I've already taken care of that The 2^16-1 is count the number of individual Godmetal (I'm calling things like Harmonium or the metal that would be created by Harmony taking up Dominion individual Godmetals) Then I alloy any number (except 0) of these 2^16-1 Godmetal, that's 2^(2^16-1)-1 It does It does too So same thing for just the total number of possible Shards? (2^16)-1? How would you calculate like, the total number of Shard Pairs? I did it manually, it’s 120, (15+14+13+12+11..... +2+1) but is there a way to calculate that in one step? What about just the total number of Shard Triplets or any other number?
2EmLee2 Posted February 25, 2021 Posted February 25, 2021 I think there is just infinity metals, with every single alloy and alloys of alloys and stuff like that. All these big numbers are hurting my brain so I'm sticking with a nice, semi- comprehensible number. 2
Frustration Posted February 25, 2021 Posted February 25, 2021 (edited) 3 minutes ago, 2EmLee2 said: I think there is just infinity metals, with every single alloy and alloys of alloys and stuff like that. All these big numbers are hurting my brain so I'm sticking with a nice, semi- comprehensible number. did you just use infinity and compresehsible in the same sentence? Edited February 25, 2021 by Frustration 1
2EmLee2 Posted February 25, 2021 Posted February 25, 2021 1 minute ago, Frustration said: did you just use infinity and compresehsible in the smae sentence? ...Maybe... Spoiler Spoiler Spoiler
mathiau he/him Posted February 25, 2021 Posted February 25, 2021 46 minutes ago, Dannex said: So same thing for just the total number of possible Shards? (2^16)-1? How would you calculate like, the total number of Shard Pairs? I did it manually, it’s 120, (15+14+13+12+11..... +2+1) but is there a way to calculate that in one step? What about just the total number of Shard Triplets or any other number? Yes, there is a way to do it one one step. If the order mattered, for the first Shard you'd have 16 possibilities and 15 for the second, that's 16*15 ordered pairs. Since there's are two possible way to order two Shards, I can just divide by two to get the number of unordered pairs, 16*15/2=120 For the triples I can do a similar reasoning, for the ordered triplets you have 16 possibilities for the first, 15 for the second and 14 for the third and there is 3!=6 ways to order a triplet, therefore 16*15*14/6=560 More generally if you have a set of n distinct object, the number of way to take k among them is n!/(k!*(n-k)!) (note that 0!=1 so it still works for n=k or k=0). If you do the simplification for k=2 you get n!/(2!*(n-2)!)=n*(n-1)/2!=n*(n-1)/2 and for k=3 you have n!/(3!*(n-3)!)=n*(n-1)*(n-2)/3!=n*(n-1)*(n-2)/6 2 minutes ago, Frustration said: did you just use infinity and compresehsible in the smae sentence? semi-comprehensible. As a physicist I agree with her interpretation 2
Halyo_Alex he/him Posted February 26, 2021 Posted February 26, 2021 1 hour ago, mathiau said: Yes, there is a way to do it one one step. If the order mattered, for the first Shard you'd have 16 possibilities and 15 for the second, that's 16*15 ordered pairs. Since there's are two possible way to order two Shards, I can just divide by two to get the number of unordered pairs, 16*15/2=120 For the triples I can do a similar reasoning, for the ordered triplets you have 16 possibilities for the first, 15 for the second and 14 for the third and there is 3!=6 ways to order a triplet, therefore 16*15*14/6=560 More generally if you have a set of n distinct object, the number of way to take k among them is n!/(k!*(n-k)!) (note that 0!=1 so it still works for n=k or k=0). If you do the simplification for k=2 you get n!/(2!*(n-2)!)=n*(n-1)/2!=n*(n-1)/2 and for k=3 you have n!/(3!*(n-3)!)=n*(n-1)*(n-2)/3!=n*(n-1)*(n-2)/6 semi-comprehensible. As a physicist I agree with her interpretation Ok yeah yknow what at this point I'll accept Infinity as the answer until someone gives us a definitive equation...
Frustration Posted February 26, 2021 Posted February 26, 2021 Just now, Halyo_Alex said: Ok yeah yknow what at this point I'll accept Infinity as the answer until someone gives us a definitive equation... at this point it might as well be. 1
Halyo_Alex he/him Posted February 26, 2021 Posted February 26, 2021 Just now, Frustration said: at this point it might as well be. Which means there's a metal that does anything you want.
mathiau he/him Posted February 26, 2021 Posted February 26, 2021 15 minutes ago, Halyo_Alex said: Which means there's a metal that does anything you want. It doesn't, infinity is so weird that sometimes there's not enough of it 1
Halyo_Alex he/him Posted February 26, 2021 Posted February 26, 2021 18 minutes ago, mathiau said: It doesn't, infinity is so weird that sometimes there's not enough of it Ok there's Countably Infinite* metals to choose from. *kind of
Bejarden he/him Posted February 26, 2021 Posted February 26, 2021 An infinite amount of metals... And we only know what some of them do... A grand total of 20 ( something like that) Anyone else depressed 3
Halyo_Alex he/him Posted February 26, 2021 Posted February 26, 2021 Just now, Bejardin1250 said: An infinite amount of metals... And we only know what some of them do... A grand total of 20 ( something like that) Anyone else depressed I mean just take a guess at what powers you want to exist and pick a metal, you'll probably get it wrong but how would we know
Bejarden he/him Posted February 26, 2021 Posted February 26, 2021 To eat and never get full Atium and iron Dont ask me to explain
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