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theTruthshaper

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Posts posted by theTruthshaper

  1. 8 hours ago, therunner said:

    True, I got a bit of a tunnel vision on the reverse lashing. But post facto rationalization, reverse lashings use the least amount of light, making them more efficient (and potentially allowing this artillery to fire more rounds before requiring restocking with spheres).

    EDIT: Also, the reverse lashing seems to be stronger than basic lashing (the whole ripping Pursuers head off incident), so for less light you get more acceleration, again increasing effectivness.

    Reverse lashings are not stronger than basic lashings, as far as I know, and Kaladin used multiple of them to rip Pursuers head off. The additional problem with this is that it gives the ammunition only a small distance to accelerate. Eg. if your railgun is a meter long, you'll need 2000 lashings to get the thing up to 200m/s (assuming each lashing is 10m/s^2)

  2. On 10/2/2021 at 11:28 PM, AonEne said:

    Hello, double post of a month because I have a dumb pun that I absolutely must share. I was making a stream to try and catch queer stuff (I have severely underutilized this feature in my time here) and decided to name it The Gay Agenda because that's more fun than 'Queer'.

    And then I think, If someone had an accent where they dropped the R at the end, 'agender' could read like 'agendah'. You could have a gay agender person and they could be the gay agenda. 

    Which is endlessly funny to me because yay puns :P 

    I suppose that you haven't seen this?

    dkxyc6da4i061.png

     

  3. 17 hours ago, therunner said:

    And in spirit of speculation, Windrunners might be able to create simple "guns/railguns" as follows: Take a long tube, put ammunition in one end, and then coat the other with a bunch of strong reverse lashings that will attract the ammunition (as reverse lashing seem to just act on object the users wants it to). When the ammunition leaves the tube, cancel the reverse lashing (this would the difficult part to time right, unless they found a way to automate it). The good thing about lashing is that they directly impart acceleration, so to accelerate heavier object you "just" need more stormlight. As an example, to accelerate arbitrary object to ~100 m/s  (assuming enough stormlight) you would need about 50m long tube and put down 10 r-lashing ( or 5 m long tube and 100 r-lashings, longer tubes are better for timing the end, and I assume strength of one lashing to be ~10m/s^2).

    You can just use normal lashings, though? I don't know why you want to use a reverse lashing. Just lash a small thing multiple times in a direction, boom, instant bullet

  4. On 21/12/2020 at 11:12 AM, G2F4E6E7E8 said:

    Let f be a real-valued function on the plane such that for every square ABCD in the plane, f(A) + f(B) + f(C) + f(D) = 0. Does it follow that f(P) = 0 for all points P in the plane?

    Yes.
    For every point P, we can take points W X Y Z, and points A B C D as such:

    temp.png.b5e3848ea276218656a9f98929399b30.png

    So, we have 4 squares, and adding the equations for each of those we get

    4*f(P) + 2*( f(W) + f(X) + f(Y) + f(Z) ) + ( f(A) + f(B) + f(C) + f(D) ) = 0

    Since the second term and the third term also represent squares, their sum is also 0.

    Thus,

    4*f(P) = 0  => f(P) = 0

    Hence, proved.

     

    On 7/2/2021 at 5:47 AM, AquaRegia said:

    Card probability problem from real life: my wife and I are playing a variant of Pinochle.  4 players, 48 card deck, 9-10-J-Q-K-A only in 4 suits, so two of each card.  Each player holds 12 cards and bidding team pass 3 cards to each other before play begins.

    If I need one specific card from my partner (say, an ace of clubs), what is the probability they will have it?

    My thoughts: I already know the card I need is NOT in the 12 I have, so it must be in one of the other 3 hands.  P=1/3 that it is in my partner's hand, yes?  That means P=2/3 that it is in one of my opponents'.  But there are TWO aces of clubs, and I only need one.  So the only BAD outcome is if BOTH of them are in my opponents' hands.

    Pbad = (2/3)(2/3) = 4/9 = 44.4%, therefore there is a 1 - 4/9 = 55.6% chance my partner has at least one of the aces I need.

    Is this the correct solution?

    And how would I extend this work to cover the case where I need TWO cards (say, K and Q of clubs)?  Is it just (5/9)(5/9) = 25/81?

    This isn't exactly right, because the probabilities of the second ace are not independent of the first.

    So,

    P(bad) = (2/3)*(23/35) = (46/105) ~ 0.438.
    

    Which implies that there is a 56.2% chance your partner has at least one of them.

    Similarly, when you need two different cards,

    P(bad) = 2*(2*23/3*35) - (2*23*22*21/3*35*34*33) ~ 0.696

    Thus, there is a 30.4% chance that your partner has at least one of both of them.

  5. 41 minutes ago, Chasmgoat said:

    Eh. First one I got.

    Ene: Sometimes I drink milk straight out of the container.
    Truth: The cow???
    Ene: What?
    Emi: Truth, W H Y?

    I love this.

     

    58 minutes ago, AonEne said:

    Ene: Connie, can I talk to you for a second?
    Connie: Yeah, what’s up? Lemme guess. You and Truth are having problems and you want me to teach you how to kiss?
    Ene: What? No, stop that. I know how to kiss. I’ve read books.

    I've read books too.
     

    Quote

    Fritz: Hey, Truth? Can I get some dating advice?
    Truth: Just because I’m with Ene doesn’t mean I know how I did it.

     

    This is practically what happened honestly.

     

  6. 2 hours ago, AonEne said:

    Hmm, what's safe to share...we take forever to get things done :P idk, the "yaoi is the same as religion" person? 

    What :blink:

    I can't figure out if this is funnier if it was said by a religious person or a yaoi person or someone who disliked both.

    (Aka we want to know more about this)

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