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Ripheus23

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Ripheus23 last won the day on November 21 2018

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  • Birthday 07/15/1986

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    Aonspren
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  1. Because the unit circle inscribes pi, but is also determined from the unit number, it arises that the increase of spheration for orthocrystalline matter is not pi itself, but pi minus 1. That is, spheration takes the orthomass and increases it (conceived as a unit of mass) by 2.14&c., as a distinctly used numerical value (not just a virtual implication of the ratio of 1/pi). So, the orthomass is, for a fraction of a second, equivalent to itself times pi. However, now we subtract 1 from pi, so the consolidated orthomass (after spheration) is 2.14&c. The loss of mass is due to the absence of a spherical tessellation of space, as such: there is a virtual "void" or "vacuum" between the unit-spheres of the pure spheration grid itself, and when this void is superimposed over the orthomassive grid, it "cuts out" or "deletes" a unit of mass for all the sections of the orthogonal tessellation that it covers. The expression, then, of the increase of spheration is:

    1 + (pi - 1) - 1 = M

    Because the virtual mass of gravity particles (as spheration) itself is less than the virtual mass of non-gravitational particles, this weakness of gravity is compounded all the more in relation to the other forces.

    ... It stands that there is an interesting infinite expression-series as:

    1 + (pi - 1) - 1 + (pi - 1) - 1 + (pi - 1) - 1 + ... &c. ...

    ---though what this entails for the doctrine of spheration, I don't know.

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