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Silverblade5

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Everything posted by Silverblade5

  1. I did? *checks* Nope, definitely spelled saxophone right.
  2. Meh, piano's overrated. Saxophone is where it's at.
  3. I'm actually fine with people not liking it as long as they give it a fair chance first. It's when they pass judgment beforehand that it really bothers me.
  4. I've said this before, and I'll say it again. Road Trip. I drive.
  5. Not if you don't want to. Sorry if that was a bit personal.
  6. Who would you say your 5 "best friends" here are?
  7. What would really make it easier on both sides is both parties deciding what they mean and want to say, and committing to that entirely.
  8. Because they're girls.
  9. Neither do I. I'd probably be near a raven primary, but I don't know what my secondary would be.
  10. I read the chart but am to lazy to make my own self-assesment Maybe someone could help me?
  11. You mean like how men are no longer being men?
  12. Same. It's things like this that make me want to literally kick people out sometimes. Besides, IMO, being an aspie is actually an improvement.
  13. If I recall correctly, the only way a dog will readily change alpha loyalty is if either something happens to her, or if a new alpha proves it's superiority by demoting him to beta,
  14. Maybe a good next step would be some cross-ship discussions?
  15. What kind of music and books are she into?
  16. Brandon dies. Who finishes the Cosmere
  17. My class just started on that as well. What are you having trouble understanding?
  18. Which unit?
  19. Check these out http://math.stackexchange.com/questions/542108/how-to-transform-a-general-higher-degree-five-or-higher-equation-to-normal-form http://math.stackexchange.com/questions/540964/how-to-solve-fifth-degree-equations-by-elliptic-functions
  20. Using resultants, you can reduce it down to the form x+a1x+a. From there, you can solve using elliptic functions.
  21. A while back, I made a post on the cubic formula. Well, I'm proud to say that I've successfully managed to derive the quartic formula as well. What I'm going to due is list the identities that lead to the eventual calculation of x, then list the actual derivation below in a spoiler box. I wouldn't mind having someone checking my math to make sure that I'm right. ax^4+bx^3+cx^2+dx+e=0 p=c/a -3b^2/8a^2 q=b^3/8a^3 -bcy/2a^2 +d/a r=cb^2/16a^3 -3b^4/256a^4 +e/a -bd/4a^2 m=-p^2/12-1 n=pr/3 -p^3/107 -q^2/8 o=(-n/2+-(n^2/4+m^3/27)^1/2)^1/3 L=o-m/3o=(((-216nm^2+24m^2(12m^2+81n^2)^1/2)^1/3)-((8m^3+54n^2-6n(12m^3+81n^2)^1/2)^1/3(-9n-(12m^3+81n^2)^1/2)))/12m^2 z=(((-216nm^2+24m^2(12m^2+81n^2)^1/2)^1/3)-((8m^3+54n^2-6n(12m^3+81n^2)^1/2)^1/3(-9n-(12m^3+81n^2)^1/2))-10pm^2)/12m^2 s=(p+2(((-216nm^2+24m^2(12m^2+81n^2)^1/2)^1/3) -((8m^3+54n^2-6n(12m^3+81n^2)^1/2)^1/3(-9n-(12m^3+81n^2)^1/2))-10pm^2)/12m^2)^1/2 t=((((-216nm^2+24m^2(12m^2+81n^2)^1/2)^1/3)- ((8m^3+54n^2-6n(12m^3+81n^2)^1/2)^1/3(-9n-(12m^3+81n^2)^1/2))-10pm^2)/12m^2)^2 +2p(((-216nm^2+24m^2(12m^2+81n^2)^1/2)^1/3) -((8m^3+54n^2-6n(12m^3+81n^2)^1/2)^1/3(-9n-(12m^3+81n^2)^1/2))-10pm^2)/12m^2+p^2-r)^1/2 y=(s+-(s^2-4(p-t+z)^1/2)/2 x=y-b/4a
  22. Someone has to be the adult around here
  23. You get upvotes. *Inserts new upvote quota*
  24. No no, I assure you it is. The fingers are merely a side effect.
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