Kelsier's Son

It doesn't necessarily mean it breaks physics; it just means that Wax moves into the realm of Rocket Physics

Hi, I'm Kelsier's son, and I may have figured out the formula for Steelpushes and Ironpulls, but specifically Steelpushes. Allow me to explain. This is all assuming the Cosmere abides by the normal laws of physics. We know, thanks to Newton, that Force is equal to mass times acceleration, F = ma. Well, what's acceleration? It's the change in velocity (Vf - Vi)/t Thus, we get F = m((Vf - Vi)/t) Now, where would we get the velocity? Well, when Vin or Wax pushes on an object, it's giving it kinetic energy, whose formula is KE = (1/2)mV^2 Solving for V, we get sqrt(m/(2KE)) Now, this energy isn't coming from nowhere. I theorize that a certain gram amount of steel/iron has a certain amount of Potential Energy, what I call Metallic Potential Energy, whose formula I have derived to be MPE = bMt, where b is the burn rate (half burn, flaring, etc.), M is the energy at b = 1, and t is time. We can set the MPE equal to the KE, so that MPE = KE, which we can substitute their respective equations: bMt = (1/2)mV^2. Solving for V, sqrt(m/(2(bMt)). Now, we can take this velocity and plug it into the force equation from earlier Fs = m((sqrt(m/(2(bMt2) - sqrt(m/(2(bMt2) )/t2 -t1). This gives us the Average force from Time one to Time two. If we want the instantaneous force, we have to get a little advanced. Let's make Fs a function of time, Fs(t), where Fs(t) is our Force equation from earlier. Let's slap a Limit in there. Now, Fs(t) = m lim(t1->t2) ((sqrt(m/(2(bMt2) - sqrt(m/(2(bMt2) )/t2 -t1). Well, wait, that's a derivative. If we take advantage of that, and do a little bit of algebra, we get Fs(t) = t/(2sqrt(2bMt/m)) This my friends is my Theory of Steelpushes I hope this makes sense. If it doesn't, I understand. .