<?xml version="1.0"?>
<rss version="2.0"><channel><title/><link>https://www.17thshard.com/blogs/blog/251-math-with-wrath/</link><description><![CDATA[<p>
	I wanted to post an SU about math, and then I decided to make a blog about it instead. So there.
</p>
]]></description><language>en</language><item><title>Rationals, P-Adics, 10-Adics and Infinity</title><link>https://www.17thshard.com/blogs/entry/1673-rationals-p-adics-10-adics-and-infinity/</link><description><![CDATA[<p>
	I am going to make a claim. Here it is:
</p>

<p>
	…000000.0000000… = 0
</p>

<p>
	…111111111.1111111111… = 0
</p>

<p>
	…222222222.22222222… = 0
</p>

<p>
	…3333333333.3333333… = 0
</p>

<p>
	(and so on for every possible digit)
</p>

<p>
	So!
</p>

<p>
	The lesson to take away
</p>

<p>
	If a single digit repeats before and after the decimal place infinitely, that number is equal to 0
</p>

<p>
	Do you want proof, my inquisitive friend?
</p>

<p>
	<img alt="🤨" data-emoticon="" src="https://cdn.jsdelivr.net/gh/twitter/twemoji@14.0.2/assets/72x72/1f928.png" />
</p>

<p>
	Well, you’ve come to the right place!
</p>

<p>
	Watson! My calculator!
</p>

<p>
	Imagine a number.
</p>

<p>
	0.111111111… (1s repeating to infinity)
</p>

<p>
	This number can be called x
</p>

<p>
	10x = 1.11111111…
</p>

<p>
	1.1111111… is just x + 1
</p>

<p>
	10x = x + 1
</p>

<p>
	9x = 1
</p>

<p>
	x = 1/9
</p>

<p>
	So, 1 repeating infinitely to the right of the decimal is equal to 1/9
</p>

<p>
	But… imagine a different number.
</p>

<p>
	Call the number y.
</p>

<p>
	y = …11111111111 (1s extending higher and higher to the left of the decimal point)
</p>

<p>
	Where x had a finite value, y is infinitely large.
</p>

<p>
	But it too has a finite value!
</p>

<p>
	“Great Scott!” - Watson
</p>

<p>
	We’ll get there.
</p>

<p>
	…111111111111111 multiplied by ten is simply …11111111111110, or y - 1
</p>

<p>
	10y = y - 1
</p>

<p>
	y = -1/9 = -x
</p>

<p>
	 
</p>

<p>
	x + y = …11111111111.11111111111…
</p>

<p>
	x + y = x - x = 0
</p>

<p>
	…111111111111.1111111111… = 0
</p>

<p>
	y is what we call a 10-adic
</p>

<p>
	An infinitely large number that is equivalent to another number
</p>

<p>
	Its called a 10 adic because it is written in base-10.
</p>

<p>
	But there’s a problem with 10-adics which I will explain elsewhere (not today, though) which makes mathematicians prefer what is called a p-adic, or prime-adic
</p>

<p>
	This is any infinite number in a prime number system
</p>

<p>
	Most common are 3-adics and 5-adics
</p>

<p>
	These are cool!
</p>

<p>
	 
</p>

<p>
	But let’s think about 17-adics
</p>

<p>
	”Great Scott!” - Watson
</p>

<p>
	It’s prime out of the goodness of my heart
</p>

<p>
	With 10-adics, it’s easy to think that the only adics that can zero out with rational pairs (y being the adic and x being the rational) are made of the numbers 1-10
</p>

<p>
	But thats not the case
</p>

<p>
	G is the highest digit in base 17, representing the value of 16
</p>

<p>
	Set …GGGGGGGG to θ
</p>

<p>
	And 0.GGGGG… to φ
</p>

<p>
	θ * 10 (since we are in base 17, this is actually times 17) is
</p>

<p>
	…GGGGGGG0, or θ - G
</p>

<p>
	10θ = θ - G
</p>

<p>
	Gθ = -G
</p>

<p>
	θ = -1
</p>

<p>
	”Great Scott!” - Watson
</p>

<p>
	Lets think about φ now
</p>

<p>
	φ * 10 = G.GGGGGGGG…
</p>

<p>
	or
</p>

<p>
	10φ=φ+G
</p>

<p>
	Gφ=G
</p>

<p>
	φ = 1
</p>

<p>
	So
</p>

<p>
	just like before
</p>

<p>
	θ = -φ
</p>

<p>
	and
</p>

<p>
	…GGGGGGGGGG.GGGGGGGGG… = 0
</p>

<p>
	<br />
	So if we increase the size of our number system, we can fit more non-zero zeros into consideration.
</p>

<p>
	But we can increase as much as our heart desires! So
</p>

<p>
	I make a rule, in base-10, to describe all rational-adic sums that are equivalento 0
</p>

<p>
	<br />
	Take a function:
</p>

<p>
	f(x) = b(a^x)
</p>

<p>
	Sum the value of the function at every single integer for x, and it will always be 0
</p>

<p>
	a and b can be any value at all.
</p>
]]></description><guid isPermaLink="false">1673</guid><pubDate>Thu, 04 Jun 2026 21:22:38 +0000</pubDate></item></channel></rss>
